Running the Python command 'Arch_CutPlane' failed:įile "/usr/lib/freecad/Mod/Arch/ArchCutPlane.py", line 69, in Activatedįile "/usr/lib/freecad/Mod/Arch/ArchCutPlane.py", line 88, in _init_ In the attached drawing, when I select in the following order "axle" then "Rectangle001", and follow the instructions here I get this error:įile "/usr/lib/freecad/Mod/Arch/ArchCutPlane.py", line 109, in previewCutVolumeĬutVolume = ArchCommands.getCutVolume(().SubObjects, ().Object.Shape) If an object is accessed using an index outside the range of a tuple, the error will be thrown.I have a slight problem with Arch CutPlane, I just wasted 4 hours getting it to work, but to no avail. The reverse index starts with -1 unto the total number of items negative. The index values starts from 0 up to the total value count. The objects are managed using the indexes. If an element is accessed outside the permitted tuple index range, then the error Inde圎rror: tuple index out of range is thrown.,The tuple is an ordered collection of objects. You can reach the elements in the tuple using reverse indexing stating -1. The tuples are indexed starting at 0 up to the total number of elements length. In this case the index error tuple index out of range will be thrown by the python tuple.,The tuple is an ordered collection of objects. The accessed index 5 is out of range of tuple.,Otherwise, at a specific index, you attempt to access an object but the object is not currently available in that index. In the example below, the index range is from 0 to 4 and reverse index is -5 to -1. The index ranges from 0 through to the total tuple items. Hence the error “Inde圎rror: out-of-range tuple index” is thrown. If an object is accessed beyond the permissible tuple range, the object can not be located at that location. Thus, the Inde圎rror: tuple index out of range is avoided, as the code does not try to access the 4th element that is out of range. It stops iterating when i=4 and it is greater than the length of the tuple. These indices are all within the range of the tuple, so the Inde圎rror: tuple index out of range error is avoided.,So, the loop runs 3 times starting from 0 and going up to 2, while i is incremented at every iteration. A print() method is called on the tuple to print out all of its elements.,The solution code executes successfully as the indices mentioned in the print() are 0,1 and 2. So the index value starts from 0 and ends at 2. This happens when you are trying to access an element that is out of bounds of the tuple.,In the code above, there is a tuple called tup having three elements. But when using tuples you might have encountered "Inde圎rror: tuple index out of range". The elements of a tuple are accessed the same way a list element is accessed – by mentioning indices. Tuples in Python are a series of objects that are immutable.
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